4x+63=4x^2

Solution for 4x+63=4x^2 equation:

4x+63=4x^2

We move all terms to the left:

4x+63-(4x^2)=0

determiningTheFunctionDomain
-4x^2+4x+63=0

a = -4; b = 4; c = +63;
Δ = b2-4ac
Δ = 42-4·(-4)·63
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*-4}=\frac{-36}{-8}
=4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*-4}=\frac{28}{-8}
=-3+1/2
$